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📅 May 17, 2026 👤 scraface

May 17, 2026

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r = \frac{A}{s} = \frac{84}{28} = 3 \text{ cm}
\text{Area} = \pi r^2 = \pi \times 3^2 = 9\pi \text{ cm}^2
Thus, the area of the inscribed circle is \(\boxed{9\pi}\).
An equilateral triangle has a side length of 10 cm. If each side is de...
The area \(A\) of an equilateral triangle with side length \(s\) is gi...
The original side length is 10 cm, so the original area is:
A_{\text{original}} = \frac{\sqrt{3}}{4} \times 10^2 = \frac{\sqrt{3}}...
The new side length is \(10 - 2 = 8\) cm. The new area is:
A_{\text{new}} = \frac{\sqrt{3}}{4} \times 8^2 = \frac{\sqrt{3}}{4} \t...
The decrease in area is:

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