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LΓΆse nach \( x \): \( 2x^2 - 8x + 6 = 0 \).
Verwende die quadratische Formel: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Hier ist \( a = 2 \), \( b = -8 \), \( c = 6 \).

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